Class 9 →
Mathematics →
Linear Equation in two variables
Q1.Which of the following option is true:
y=3x+5 has
Aa unique solution
B3 solutions
C2 solutions
Dinfinitely many solutions
Q2.3x+10 will have:
AUnique solution
BTwo solutions
CInfinitely many solutions
DNo solution
Q3.The solution of the equation 2x+y=7 is:
A(0,5)
B(5,1)
C(1,5)
D(3,2)
Q4.The solution of the equation x=4y is:
A(4,1)
B(1,4)
C(-1,-4)
D(-1,4)
Q5.The solution of the equation πx+y=9 is:
A(9,0)
B(0,9)
C(-9,1)
D(1,-9)
Q6.If (2,1) is the solution of the equation 2x+3y=k, then the value of k is:
A7
B6
C-7
D9
Q7.Which of the following is a solution of the equation x-2y=4?
A(0,2)
B(1,1)
C(4,0)
D(2,0)
Q8.If (4,19) is a solution of the equation y=ax+3, then equals:
A3
B4
C5
D6
Q9.If (a,4) lies in 3x+y=10, then the value of 'a' is:
A3
B1
C2
D4
Q10.How many linear equations are satisfied by x=2 and y=-3?
AOnly one
BTwo
CThree
DInfinitely many
Q11.If x=-1,y=2 is a solution of the equation 2x-y=6, then the value of k is:
A1
B3
C5
D6
Q12.The solution of the equation 3x+4y=7 is:
A(1,1)
B(-1,1)
C(1,-1)
D(0,1)
Q13.The solution of the equation x=6y is:
A(6,1)
B(2,3)
C(3,-2)
D(1,6)
Q14.The solution of the equation x=6y is:
A(-2,\( \frac{3}{2} \))
B(2,\( \frac{1}{3} \))
C(0,2)
D(\( \frac{1}{3} \),2)
Q15.The solution of the equation 3x+4y=7 is:
A(-3,4)
B(3,4)
C(4,3)
D(4,2)
Q16.Which of the following is not a solution of 2x+y=7?
A(0,7)
B(1,5)
C(2,3)
D(3,2)
Q17.Which of the following is not a solution of x=4y?
A(0,0)
B(1,4)
C(4,1)
D(1,0)
Q18.x=3, y=-2 is a solution of the equation
Ax+y=5
B3x-2y=11
C4x-3y=18
D3x+y=5
Q19.If (2,0) is the solution of the linear equation 2x+3y=k, then the value of k is :
A4
B6
C5
D2
Q20.If (1,1) is a solution of the equation 5x+2ky=3k, then the value of k is:
A3
B4
C5
D6
Q21.The equation of x-axis is of the form:
Ax=0
By=0
Cx+y=0
Dx=y
Q22.The equation x=7 in two variables can be written as:
A0x+0y=7
B0x+1y=7
C1x+1y=7
D1x+0y=7
Q23.The graph if the linear equation 2x+3y=6 cuts the y-axis at the point:
A(3,0)
B(0,3)
C(0,2)
D(2,0)
Q24.The equation 5y=2 can be written as an equation in two variables as:
Ax+5y=2
B5y-2=0
Cx-5y-2=0
D0x+5y-2=0
Q25.Expressing y=2 in the form ax+by+c=0, the value of 'a' equals:
A0
B1
C2
D-2
Q26.Any point on the line y=x is of the form:
A(a,0)
B(a,a)
C(0,a)
D(a,-a)
Q27.Tiya went to a stationery shop to buy some pen. The cost of the ball pen was ₹5 less than half of the cost of a fountain pen. The given information expressed as a linear equation in two variables is:
Ax+5y+0=0
Bx-5y+0=0
C2x=5y
Dx-\( \frac{y}{2} \)-5=0
Q28.A student bought some books and pens. The cost of the book was ₹20 more than the cost of a pen. The linear equation taking the cost of book as ₹b and cost of pen as ₹p is:
Ab+2p-20=0
Bb-2p-20=0
Cb+p=0
Db-p=0
Q29.The equation y=k in two variables can be written as:
AOx+1y=k
B1x+1y=k
C1y+1k=0
D1y-1k=0
Q30.The standard form of the linear equation y-x in two variables is:
A1x+1y-7=0
B1x-1y-7=0
C-1x+1y-7=0
D1x+1y+7=0
Q31.In the equation 2x=-5y, the values of a,b,and c respectively are:
A2,-5,0
B-2,5,0
C2x,-5y,0
D2,5,0
Q32.Any equation in the form ax+by+c=0 where a,b and c are real numbers and a, b≠0, is called a :
ALinear equation in 3 variables
BLinear equation in 5 variables
CLinear equation in 2 variables
DLinear equation in real numbers
Q33.In a ODI cricket match between India and Sri Lanka played in Mumbai, two Indian batsmen together scored 176 runs.
Which equation satisfies the above equation?
Ax+176=y
Bx+y=176
Cy+176=x
Dxy=176
Q34.On his birthday, Nito donated 4 chocolates each to children and 3 chocolates to adults in a small orphanage centre. Teh linear equation representing the above situation if he distributed 50 total chocolates is:
Ax-y=50
B4x+3y=50
Cx-3y=50
D3x+4y=50
Q35.For the equation x=y, the values of a,b ans c are:
A1,1 and 1
B1,-1 and 0
C1,1 and 0
D-1,-1 and 0
Q36.If a=3, b=-5 and c=4, then which one is the correct linear equation in two variables?
A3x+4=-5y
B3x+4=5y
C3x-5y=4
D3x=-5y+4
Q37.Mary's mother went to the local market to buy some groceries. She found that the cost of 1 kg of potato was 10 times the cost of 1 kg of tomato. The linear equation satisfying the situation is:
Ax+y=10
Bx-y=10
Cxy=10
Dx-10y=0
Q38.The equation of y-axis is of the form:
Ax=0
By=0
Cx=y
Dx+y=0
Q39.The linear equation 2x=5y-7 can be written as: